When using H2/Pd to reduce an Alkene, will the hydrogens be added syn or anti?
Syn. Reduction with H2/Pd will always add hydrogens syn to each other.
Determine the point groups for: a) Napththalene b) Acetylene c) Dibensenechromium (eclipsed)
a) D(2)h b) D(infinity)h c) D(6)h
In each of the following pairs, pick the element with the higher ionization energy. Explain your choice. a) Kr and Br b) He and Ne c) N and O
a) Kr - Ionization energy (generally) increases across the periodic table due to the decrease in atomic radius, which pulls the outer electrons closer to the nucleus, making it harder to remove the outer electrons. b) He - Ionization energy decreases going down a column of the periodic table because of the shielding from the inner electrons. Outer electrons are less closely held going down a column. c) N - this is tricky because it does not follow the normal trends. N has a higher ionization energy due to it's half filled 2p configuration; it is more stabilized than O's 2p orbital. Therefore it is easier to remove an electron from O than N.