Tutor profile: Kyle B.
Subject: Basic Math
In a math problem such as 2 x (5 - 6) + 10 how do I know where to start
You can tell where to start a problem like this by remembering the order of operations. Order of operations is basically a list of what you have to do first which goes Brackets Exponents Division & Multiplication Addition & Subtraction An easy way to remember this is by memorizing the acronym BEDMAS. So lets try it out together. First step is to solve the any math within brackets. In our case this is (5 - 6) 2 x (5 - 6) + 10 2 x ( - 1 ) +10 Next we move onto exponents, but in our problem we don't have any so we can move on to Division and multiplication. If you have a problem with multiplication and division it does not matter which you do first. 2 x ( - 1 ) +10 - 2 + 10 Lastly we move to addition and subtraction. Once again if you have a problem with addition or subtraction it does not matter which you do first. -2 + 10 8 And now we know our answer is 8
Subject: Civil Engineering
How would you design a tension member using structural steel using Canadian Design Standards?
First I would determine the factored loads using the the factored load cases based on the National Building Code of Canada. This would give me my factored tension force the is being applied on the member, Tf ( the 'f' denotes that it is factored). Next I choose the strength of the steel I would use denoted as Fy which has units of MPa. Typically we use 350 MPa. I would then select the proper code which depends on your building material. For structural steel in Canada we use S16-14 Design of Steel Structures. Next I would find the applicable code for structural steel tension members. Clause 13.2 Axial tension, states that the tensile resistance for a tension member as Tr = Phi x Ag x Fy Where Phi is a safety factor of that is equal to 0.9 Ag is the gross cross-sectional area (typically we use units of mm^2) and Fy is the strength of the material. To design a safe tension member we must ensure that Tf < Tr, therefore I can rewrite Clause 13.2 as: Tf < Phi x Ag x Fy After I will rearrange this equation to solve for the required cross-sectional area ensuring I use proper unit conversion ( 1 MPA = 1 N / mm ^2) Ag > Tf / (Phi x Fy) Once I have determined the required area I need for the tension member I would go to my member properties tables, which starts on page 6-36 and select a member that has a cross-sectional area that satisfies the equation. Lastly with the member and strength of the material I selected I would then ensure Tr > Tf by using clause 13.2 Tr = Phi x Ag x Fy
What are the steps to solve a simple algebraic equation such as 16x - 5 = 28 + 7x?
First I would move similar terms to the same side I would move the positive 7x term to the left side by subtracting 7x from both sides and I would then collect like terms 16x -5 - 7x = 28 + 7x - 7x 9x - 5 = 28 I would then move the -5 to the right side by adding 5 to both sides and collecting like terms again 9x - 5 + 5 = 28 +5 9x = 33 Lastly, once all my x terms are on the same side alone, I would divide both sides by the number in front of the x term which is 9 9x/9 = 33/9 x = 33/9 From here I would check if the the question requires the final answer as a fraction or a decimal
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