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# Tutor profile: Tenti T.

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Tenti T.
Tutor for 3 years
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## Questions

### Subject:Applied Mathematics

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Question:

Solve the following expression for x: \$log_2(x) = 3\$

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Tenti T.

To solve this expression we need to use the definition of logarithms which states that if: \$\$log_{a}(b) = c\$\$ then it is also true that \$\$a^c = b\$\$ so using the above definition with a = 2 , b = x and c = 3 we write \$\$log_{2}(x) = 3\$\$ then it is also true that \$\$2^3 = x\$\$ \$\$x = 2^3\$\$ \$\$x = 8\$\$

### Subject:Calculus

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Question:

Find the first derivative of the following expression \$\$f(x) = 2x^{3} \$\$

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Tenti T.

so we re write the expression as \$\$f'(x) = (2x^{3})'\$\$ the constant goes out of the derivative : \$\$f'(x) =2 (x^{3})'\$\$ now using the formula \$\$(x^{n} )'= n x^{n-1}\$\$ where n = 3 : \$\$f'(x) =2(3)(x^{3-1})'\$\$ This is our answer : \$\$f'(x) = 6x^{2}\$\$

### Subject:Algebra

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Question:

Solve the following systems of equations : 3x+5y = 7 3x + 4y = 1

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Tenti T.

by subtracting the first equation from the second we have : \$\$3x-3x+5y - 4y = 7 - 1\$\$ \$\$y = 6\$\$ now we substitute the value of y we found in the first equation and we get : \$\$3x + 5(6) = 7\$\$ \$\$3x = 7-30\$\$ \$\$3x = -23\$\$ \$\$x= -\dfrac{23}{3}\$\$

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