# Tutor profile: Manish R.

Inactive

Manish R.

Cleared the Toughest exam of Asia IIT-JEE

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## Questions

### Subject: Hindi

TutorMe

Question:

How to say " where are you from ? "

Inactive

Manish R.

Answer:

" app kahan se ho ? "

### Subject: Geometry

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Question:

The semicircle of area 1250 pi centimeters is inscribed inside a rectangle. The diameter of the semicircle coincides with the length of the rectangle. Find the area of the rectangle.

Inactive

Manish R.

Answer:

Let r be the radius of the semicircle. Area of the semicircle is known; hence 1250Pi = (1/2) Pi r2 (note the 1/2 because of the semicircle) Solve for r: r = 50 Length of rectangle = 2r = 100 (semicircle inscribed) Width of rectangle = r = 50 (semicircle inscribed) Area = 100 * 50 = 5000

### Subject: Basic Math

TutorMe

Question:

The value of x + x(x^x) when x = 2 is:

Inactive

Manish R.

Answer:

x + x(x^x) Put the value of x = 2 in the above expression we get, 2 + 2(2^2) = 2 + 2(2 × 2) = 2 + 2(4) = 2 + 8 = 10

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