Subjects
PRICING
COURSES
SIGN IN
Start Free Trial
Cj A.
Detailed Engineer and Math Lover
Tutor Satisfaction Guarantee
Pre-Calculus
TutorMe
Question:

How do you find the limit of |x|/x as x approaches 0?

Cj A.
Answer:

For x<0, |x|/x=−x/x=−1 For x>0, |x|/x=x/x=1 Thus limx→0−|x|/x=−1 limx→0+|x|/x=1 So the limit does not exist.

Calculus
TutorMe
Question:

How do you find the second derivative of x^2*y^2=1?

Cj A.
Answer:

First we need to find the first derivative of the function. We will do this using implicit differentiation. With this particular function we will use the product rule. 2xy^2+x^2(2y)(dydx)=0 Now subtract 2xy^2 from both sides x^2(2y)dydx=−2xy^2 Divide both sides by x^2(2y) dydx=−2xy2x^2(2y) Which simplifies to dydx=−yx Now for the second derivative we will use the quotient rule d^2ydx^2=(x(−1)dydx)−(1(−y))x^2 d^2ydx^2=−xdydx+yx^2=y−xdydxx^2 plug dydx into the right hand side d^2ydx^2=y−x(−yx)x^2=y+yx2=2yx^2 d^2ydx^2=2yx^2

Algebra
TutorMe
Question:

Solve this system of equations 4x + y = 16 (1) 2x + 3y = 18 (2)

Cj A.
Answer:

First thing you want to do is create like terms in both equations. So go ahead and multiple equation (2) by 2 That's going to give you 4x + 6y = 36. Now we have the like term (4x) in both equations and we can subtract to temporarily cancel out x. Subtract (1) from (2) (4x-4x) + (6y-y) = (36-16) 5y = 20 Solve for y => y = 20/5 = 4. Now plug y=4 in Equation (1) 4x + 4 = 16 x = 12/4 = 3.

Send a message explaining your
needs and Cj will reply soon.
Contact Cj
Ready now? Request a lesson.
Start Session
FAQs
What is a lesson?
A lesson is virtual lesson space on our platform where you and a tutor can communicate. You'll have the option to communicate using video/audio as well as text chat. You can also upload documents, edit papers in real time and use our cutting-edge virtual whiteboard.
How do I begin a lesson?
If the tutor is currently online, you can click the "Start Session" button above. If they are offline, you can always send them a message to schedule a lesson.
Who are TutorMe tutors?
Many of our tutors are current college students or recent graduates of top-tier universities like MIT, Harvard and USC. TutorMe has thousands of top-quality tutors available to work with you.