TutorMe homepage

SIGN IN

Start Free Trial

Barsha B.

Tutoring since 2016

Tutor Satisfaction Guarantee

Trigonometry

TutorMe

Question:

find tan495 without using a calculator.

Barsha B.

Answer:

Solution Here 495 is more than a round which is 360 degrees and less than two rounds which is 720 degrees. so, do 495-360=135 Now, look at 135 and always, take a reference to 0 degrees, 180 degrees and 360 degrees. Which one do you think is the nearest from 135? It's obviously, 180. so now take a reference with 180 and write your angle in terms of sum or difference with180 tan135= tan(180-45) Now, which quadrant does 135 lie? It lies in the 2nd quadrant and you have only Sin and its opposite(CSC) positive on that quadrant making rest of others negative so the value we're getting will be negative. And for the value, we look at 45. What is tan45? Yes, It's 1. so tan135 is going to be-1.

Geometry

TutorMe

Question:

right angle triangle has an exterior angle from a side as 130 degrees such that the 90-degree angle is its nonadjacent angle. find the other nonadjacent angle.

Barsha B.

Answer:

Solution: There are two ways to solve this. First method, the sum of non-adjacent angles is equal to the exterior angle so, 90+X =130 -90 -90 X= 40 degrees answer Second method, the angled interior adjacent to that angle is supplementary to that adjacent angle so that angle will be 180-130=50 degrees. Now, we have two angles of the triangle, and we know that the sum of the angles in triangle is 180 degrees so' 90+50+X=180 140+X=180 combining like terms -140 -140 X=40 degrees answer

Algebra

TutorMe

Question:

F(x)=X^2 +5X-KX+6,x+3 is the factor of this polynomial. find k.

Barsha B.

Answer:

solution: If F(X) is divisible by X-a, F(a)=0. here, F(X) is divisible by X-3, So, F(3) should be =0 so we obtain an equation f(3)=0 3^2+5(3)-k(3)+6=0 [x substituted with 3] 9+15-3k+6=0 20-3K=0 [combining like terms] -20 -20 -3k=-20 -3k/-3 =-20/-3 [dividing both side by -3] k=-20/3 answer

Send a message explaining your

needs and Barsha will reply soon.

needs and Barsha will reply soon.

Contact Barsha

Ready now? Request a lesson.

Start Session

FAQs

What is a lesson?

A lesson is virtual lesson space on our platform where you and a tutor can communicate.
You'll have the option to communicate using video/audio as well as text chat.
You can also upload documents, edit papers in real time and use our cutting-edge virtual whiteboard.

How do I begin a lesson?

If the tutor is currently online, you can click the "Start Session" button above.
If they are offline, you can always send them a message to schedule a lesson.

Who are TutorMe tutors?

Many of our tutors are current college students or recent graduates of top-tier universities
like MIT, Harvard and USC.
TutorMe has thousands of top-quality tutors available to work with you.

Made in California

© 2019 TutorMe.com, Inc.