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Tutor profile: Reid B.

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Reid B.
Post-Grad Ecology and Anthropology Student
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Questions

Subject: Writing

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Question:

There is no smooth link between these two paragraphs. Read them, and write a transition sentence or two that helps connect them and maintains a consistent plot line: I had never seen my old dog Sally bark until the last summer before I started college. Day in and day out, Sally loyally guarded her bed on the porch with her tail wagging and her tongue tasting the cool sea breeze. I could tell something was wrong that day when her panting went silent and her hackles went up. The snaps of sticks off in the distance were enough to launch her off the porch barreling toward the forest. The wolf attempted to lunge at Sally. Far from her normally quiet demeanor, Sally retorted with ferocious barks and growls, jumping out of the way last second to avoid injury. She paid no heed to my cries for her to return to the porch. She was busy defending my family! After several attacks, the wolf finally grew bored and trotted off in the opposite direction looking mildly annoyed. Sally saved our family!

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Reid B.
Answer:

At the end of paragraph 1: Before I could call out to stop her, I saw a massive shadow far off that sent chills down my spine- she was running toward a wolf. The issue with the second paragraph is that it describes a wolf not yet introduced in the plot line. This could be confusing to readers, who want to know where characters come from and why. To avoid this, writers use transition sentences to try to hint at what is to come in the next paragraph.

Subject: Biology

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Question:

What are the three different types of photosynthesis? Compare and contrast them.

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Reid B.
Answer:

The photosynthesis pathway used by a plant is dictated by the amount of water available as well as the temperature of its environment. PS = photosynthesis C3: The most common form of PS, C3 occurs in a way where CO2 uptake is not separated spatially or temporally from the Calvin cycle like C4 and CAM PS (see later). Stomata are open during the day, which allow considerable water loss, but this is not as problematic, because these plants, which include oats, rice, and soybean, typically live in cooler, wetter areas, so they can take in water just as readily. C4: C4 PS occurs in environments that are hot, dry, bright, and low in CO2. To maximize CO2 uptake, CO2 absorption occurs separately from Calvin cycle and is catalyzed by the presence of phosphoenolpyruvate or PEP. PEP helps in C4 PS, because it attracts more CO2 than O2 for the Calvin cycle which prevents photorespiration, a process where plants absorb O2 and release CO2 (basically reverse PS). As a result, the plant is more efficient at absorbing CO2 and thus needs to stay open less time during the hot day, meaning it loses less water. Some C4 plants include corn and sugarcane. CAM: Short for Crassulacean Acid Metabolism, CAM occurs in the hottest, driest climates. To conserve water, these plants open their stomata at night for CO2 uptake, because the cooler temperature of night will minimize evapotranspiration. Additionally, at night, CAM plants combine CO2 with phosphoenolpyruvate to form oxaloacetic acid, which is stored as a 4 carbon compound called malic acid in cell vacuoles. In the morning, when temperatures begin to rise again, the plant releases the malic acid from the vacuoles, which then returns to its form as CO2 and enters the Calvin cycle. Some CAM plants include cacti.

Subject: Algebra

TutorMe
Question:

Maria the farmer sells her chickens' eggs at a market every Saturday. This week, her chickens produced 180 eggs for Saturday. Due to container size, Maria can only sell the eggs in quantities of one dozen (x) or half a dozen (y). If 6 people buy a half dozen eggs, how many people bought a dozen eggs?

Inactive
Reid B.
Answer:

What we know is that Maria sells eggs as a dozen or a half dozen. We also know that she can sell up to 180 eggs. What we do not know is how much of each quantity she sells. Therefore the unknown variables are x (how many dozens sold) and y (how many half-dozens sold). Algebraically, we write this as: 12x + 6y = 180. We have two unknown variables, which is not very helpful, but we were given information that 6 people bought half a dozen eggs. Now we know that y = 6, so we can plug y in to the equation, which gives us: 12x + 6(6) = 180. We are left with one unknown variable now, which is totally doable to solve! Let's see what we get. 12x + 6(6) = 180 -> 12x + 36 = 180 ------- now subtract 36 from both sides to get 12x by itself -> 12x = 144 ------ now divide both sides by 12 to get x by itself -> x = 12 ------ so we've solved for x, but we cannot forget units -> x = 12 dozen eggs. Maria sold 6 half dozen eggs and 12 dozen eggs. If we plug this back into the equation, we get: 12(12) + 6(6) = 180 -> 144 + 36 = 180 -> 180 = 180

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