Prove SinA CscA - Sin^2A= Cos^2A
(According to reciprocal identities, 1/sinA=CscA) SinA (1/Sin A)- Sin^2A =1 - Sin^2 A (this is similar to the Pythagorean theorem trig identity( Sin^2A+Cos^2A=1)) =Cos^2 A
What is the role of the rough endoplasmic reticulum compared to the smooth endoplasmic reticulum?
Rouch endoplasmic reticulum contains ribosomes and it functions to permit the translation of protein that has been destined for secretion while the smooth ER lacks ribosomes and it helps in detoxification and lipid synthesis.
add 3x^2 + 2x + 3 and 5x^2 - 7x
Start by combining like terms together first then simplify =3x^2 +5x^2 +2x- 7x + 3 =8x^2-5x+3