If 0 < t < 2π such that sin t = √2 / 2 and cot t < 0, then t = ?
Since in Second Quadrant Sin is positive and Cot is negative. It is given sin t = √2 / 2 , sin t = 1/ √2. t can be π/4 or 3π/4, Since Cot t < 0 which is in the second quadrant (π/2 <t<π) So Ans will be t = 3π/4.
The two functions f and g defined by f(x) = 3x + 3 for x real and g(t) = 3t + 3 for t real and positive are equal?
False. Two functions are equal if their rules are equal and their domains are the same.
Find the equation of the line that passes through the points (-1, -1) and (-1, 2).
To find the equation of the line through the points (-1, -1) and (-1, 2), we first use the slope m. m = (y2 - y1) / (x2 - x1) = (2 - -1) / (-1 - -1) = 3 / 0 The slope is undefined which means the line is perpendicular to the x-axis and its equation has the form x = constant. Since both points have equal x coordinates -1, the equation is given by: x = -1