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Vibhav G.

Assistant Manager in Process at Aditya Birla Group

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Trigonometry

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Question:

If 0 < t < 2π such that sin t = √2 / 2 and cot t < 0, then t = ?

Vibhav G.

Answer:

Since in Second Quadrant Sin is positive and Cot is negative. It is given sin t = √2 / 2 , sin t = 1/ √2. t can be π/4 or 3π/4, Since Cot t < 0 which is in the second quadrant (π/2 <t<π) So Ans will be t = 3π/4.

Calculus

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Question:

The two functions f and g defined by f(x) = 3x + 3 for x real and g(t) = 3t + 3 for t real and positive are equal?

Vibhav G.

Answer:

False. Two functions are equal if their rules are equal and their domains are the same.

Algebra

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Question:

Find the equation of the line that passes through the points (-1, -1) and (-1, 2).

Vibhav G.

Answer:

To find the equation of the line through the points (-1, -1) and (-1, 2), we first use the slope m. m = (y2 - y1) / (x2 - x1) = (2 - -1) / (-1 - -1) = 3 / 0 The slope is undefined which means the line is perpendicular to the x-axis and its equation has the form x = constant. Since both points have equal x coordinates -1, the equation is given by: x = -1

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