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Basim A.

Electrical Engineer with tutoring experience and certification

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Pre-Calculus

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Question:

Find $$\vec{x}$$, where $$\vec{x}=\vec{u} + \vec{v}$$ : $$\vec{u} = (4 , 1)$$ $$\vec{v} = (10 , -5) $$

Basim A.

Answer:

$$\vec{x}=\vec{u} + \vec{v} = (4 + 10, 1 + (-5)) = (14,-4)$$

Calculus

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Question:

Find the limit as $$x$$ approaches infinity $$(+\infty)$$ for: $$\lim_{x \to \infty} f(x) =\frac{(x + 2)^2} {x}$$

Basim A.

Answer:

$$ f(x) =\frac{(x + 2)^2} {x} = \frac{x^2 + 4x + 4}{x} = x + 4 + \frac{4}{x}$$ $$\lim_{x \to \infty} f(x) = \infty + 4 + \frac{4}{\infty} = \infty + 4 + 0 = \infty$$

Algebra

TutorMe

Question:

Find the value of $$x$$: $$4(x-3) = 10$$

Basim A.

Answer:

To find $$x$$: $$4x - (3*4) = 12$$ $$4x - 12 = 12$$ $$4x = 12 + 12$$ $$4x = 24$$ $$x = \frac{22}{4} = 6$$

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