TutorMe homepage
Subjects
PRICING
COURSES
SIGN IN
Start Free Trial
Basim A.
Electrical Engineer with tutoring experience and certification
Tutor Satisfaction Guarantee
Pre-Calculus
TutorMe
Question:

Find $$\vec{x}$$, where $$\vec{x}=\vec{u} + \vec{v}$$ : $$\vec{u} = (4 , 1)$$ $$\vec{v} = (10 , -5)$$

Basim A.
Answer:

$$\vec{x}=\vec{u} + \vec{v} = (4 + 10, 1 + (-5)) = (14,-4)$$

Calculus
TutorMe
Question:

Find the limit as $$x$$ approaches infinity $$(+\infty)$$ for: $$\lim_{x \to \infty} f(x) =\frac{(x + 2)^2} {x}$$

Basim A.
Answer:

$$f(x) =\frac{(x + 2)^2} {x} = \frac{x^2 + 4x + 4}{x} = x + 4 + \frac{4}{x}$$ $$\lim_{x \to \infty} f(x) = \infty + 4 + \frac{4}{\infty} = \infty + 4 + 0 = \infty$$

Algebra
TutorMe
Question:

Find the value of $$x$$: $$4(x-3) = 10$$

Basim A.
Answer:

To find $$x$$: $$4x - (3*4) = 12$$ $$4x - 12 = 12$$ $$4x = 12 + 12$$ $$4x = 24$$ $$x = \frac{22}{4} = 6$$

Send a message explaining your
needs and Basim will reply soon.
Contact Basim
Ready now? Request a lesson.
Start Session
FAQs
What is a lesson?
A lesson is virtual lesson space on our platform where you and a tutor can communicate. You'll have the option to communicate using video/audio as well as text chat. You can also upload documents, edit papers in real time and use our cutting-edge virtual whiteboard.
How do I begin a lesson?
If the tutor is currently online, you can click the "Start Session" button above. If they are offline, you can always send them a message to schedule a lesson.
Who are TutorMe tutors?
Many of our tutors are current college students or recent graduates of top-tier universities like MIT, Harvard and USC. TutorMe has thousands of top-quality tutors available to work with you.
Made in California
© 2018 TutorMe.com, Inc.