Write a paragraph outlining the process of finding the perfect tutor. Include at least one in-text citation.
Finding the perfect tutor is no easy task. In fact, many have tried and most have failed. Seekers often take the wrong approach from the start when they ask a friend or family member for help. "Though family loves you dearly, they are not always the best to teach you," says perfect tutoring expert Tutor McExpertson (375). Many experts suggest beginning the journey on tutorme.com, a website which "completely revolutionized the ultimate search" (O'Tutor 176). Once on the website, it is all about examining the personal and intellectual fit between tutor and student. Most importantly, when looking for the perfect tutor, never discount a quirky yet compelling paragraph.
Consider the following scenario: Marie is playing by herself with a toy truck. Jack comes and takes the truck away from Marie. Marie begins to scream and shove Jack. The teacher, having seen the events unfold, takes the truck from Jack and gives it back to Marie. Describe the antecedent and consequence of Marie's screaming and shoving. Was her behavior likely reinforced or punished? How might this incident affect Marie's behavior in the future?
Antecedent: Jack takes the toy truck from Marie. Consequence: Teacher gives Marie the truck. Marie's screaming and shoving were likely positively reinforced by the presence of the truck. In the future, Marie is likely to scream and shove more often as a means of getting what she wants.
Write an equation for finding the confidence interval of a sample size n=16 with mean x=5 and a sample standard deviation s=1. Use a confidence level C=99%. What does this confidence interval tell us about the true population means?
First, find t to use as critical value: To find t, find degrees of freedom (n-1): 16-1=15 Look up the t value in at-distribution table with df=15 and p=0.01 (1-[C/100]): t=2.60248 Second, find the lower boundary of the interval (x-t[s/√n]): 5-2.60248(1/√16) 5-2.60248(1/4) 5-2.60248(0.25) 5-0.65062 4.34938 is the lower boundary Third, find the upper boundary of the interval (x+t[s/√n]): 5+2.60248(1/√16) 5+2.60248(1/4) 5+2.60248(0.25) 5+0.65062 5.65062 is the upper boundary Finally, present the confidence interval as a whole: (4.34938, 5.65062) Based on these results, we are 99% confident that the mean of the population is between 4.34938 and 5.65062