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# Tutor profile: Satyam C.

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Satyam C.
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## Questions

### Subject:Trigonometry

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Question:

If cos(x+y)=$$\frac{4}{5}$$ and sin(x-y)=$$\frac{5}{13}$$ Find tan(2x)??

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Satyam C.

=tan(2x) =tan(x+y+x-y) =$$\frac{tan(x+y)+tan(x-y)}{1-tan(x+y)tan(x-y)}$$ =$$\frac{ \frac{3}{4}*\frac{5}{12} }{1-\frac{3}{4}*\frac{5}{12}}$$ =$$\frac{5}{11}$$

### Subject:Calculus

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Question:

$$\int xsinx,\mathrm{d}x$$

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Satyam C.

x$$\frac{-cos2x}{2}$$ - $$\int \frac{-cos2x}{2},\mathrm{d}x$$ $$\frac{-xcos2x}{2}$$ +$$\frac{1}{2}$$$$\int \frac{cos2x}{2},\mathrm{d}x$$ $$\frac{-xcos2x}{2}$$+$$\frac{1}{2}$$$$\frac{sin2x}{2}$$+k $$\frac{-xcos2x}{2}$$+$$\frac{sin2x}{4}$$+k

### Subject:Algebra

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Question:

solve for x: |x-2|=|2x-6|

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Satyam C.

a point at which nature change are x=2, 3 case 1: For x<2 -(x-2)=-(2x-6) x-2=2x-6 x=4 But we have assume x<2, this is not possible case 2: For 2<x<3 x-2=-(2x-6) x-2=6-2x 3x=8 x=8/3 case 3: For x>3 x-2=2x-6 x=4 Hence, solution is x=8/3 and x=4

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