Menaga S.

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Pre-Algebra

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Question:

Factor the following equation: x^2-3x-40

Menaga S.

Answer:

(x+5)(x-8)

Basic Math

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Question:

If (0.2)^x = 2 and log 2 = 0.3010, find the value of x to the nearest tenth.

Menaga S.

Answer:

(0.2)^x = 2. Taking log on both sides log (0.2)^x = log 2. x log (0.2) = 0.3010, [since log 2 = 0.3010]. x log (2/10) = 0.3010. x [log 2 - log 10] = 0.3010. x [log 2 - 1] = 0.3010,[since log 10=1]. x [0.3010 -1] = 0.3010, [since log 2 = 0.3010]. x[-0.699] = 0.3010. x = 0.3010/-0.699. x = -0.4306…. x = -0.4 (nearest tenth)

Differential Equations

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Question:

y= 2x+1 Find dy/dx.

Menaga S.

Answer:

dy/dx= 2(1) x^(1-1) =2

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