You are given a non-empty list which contains the names and order of the rankings from a race with an unknown number of participants, write the code to print the name of the person who came in last. ** Name of the list is "rankings"

length = len(rankings) last_place = length - 1 loser = rankings[last_place] print("Last place: %s" % loser")

Sally and Jimmy have saved 20 coins to buy bubblegum, If Sally has 10 quarters and Jimmy has 10 dimes how much money have they saved all together?

Sally has $$10$$ quarters : - one quarter is a worth $$25$$ cents or $$.25$$ - if Sally has $$10$$ of them then that's ten times the worth of one quarter - so Sally has this much money: $$ 10 * .25 $$ - $$ 10 * .25 = 2.50$$ - we know Sally has $2.50 Jimmy has $$10$$ dimes : - one dime is a worth $$10$$ cents or $$.10$$ - if Jimmy has $$10$$ of them then that's ten times the worth of one dime - so Jimmy has this much money: $$ 10 * .10 $$ - $$ 10 * .10 = 1.00$$ - we know Sally has $1.00 ***************************** To get what they have saved all together we need to take what Sally has and what Jimmy has: - Sally: $2.50 - Jimmy: $1.00 $2.50 + $1.00 = $3.50 ***************************** All together they have saved : $3.50

Simplify the following expression: $$(3x + 2)(x + 5)$$ Solve as if : $$x = 4$$

To simplify the expression let's start by using the FOIL technique: FOIL - First.Outside.Inside.Last $$ (3x + 2) (x + 5) $$ First (Product of the First term from each group) : $$ 3x * x = 3x^2 $$ Outside (Product of First term from group 1 and Second term from from group 2) : $$ 3x * 5 = 15x $$ Inside (Product of Second term from group 1 and First term from from group 2) : $$ 2 * x = 2x $$ Last (Product of the Second term from each group) : $$ 2 * 5 = 10 $$ ****************************************** Now add all of the products to get: $$ 3x^2 + 15x + 2x + 10 $$ ****************************************** Simplify by adding like terms : $$ 3x^2 + 17x + 10 $$ ****************************************** Solve $$ 3x^2 + 17x + 10 $$ as if : $$ x = 4 $$ ... $$ 3(4)^2 + 17(4) + 10 $$ --> $$ 3(16) + 17(4) + 10 $$ --> $$ 48 + 68 + 10 $$ --> $$ 116 + 10 $$ --> $$ 126 $$