Enable contrast version

# Tutor profile: Hritik S.

Inactive
Hritik S.
Engineer by Profession, Tutor by Choice (3+ years)
Tutor Satisfaction Guarantee

## Questions

### Subject:Basic Math

TutorMe
Question:

sum it 4.7+0.9+0.01=?

Inactive
Hritik S.

answer : 4.7+0.9+0.01 =4.7+0.91 = 5.61

### Subject:Calculus

TutorMe
Question:

What is the slope of tangent line of function f(x)= -4$$x^{2}$$+3$$x$$-4 at $$x$$=2?.

Inactive
Hritik S.

slope of tangent will be = f'($$x$$) at $$x$$=2 Therefore f'($$x$$)= -8$$x$$+3 f'(2)= -8*2+3 = -16+3 = -13 slope = -13.

### Subject:Algebra

TutorMe
Question:

The equation $$\frac{24x2+25x−47}{ax−2}$$ =$${−8x−3}$$−$$\frac{53} {ax−2}$$ is true for all values of x≠$$\fra2 a , where a is a constant. What is the value of a? Inactive Hritik S. Answer: Multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have: 24$$x^{2}$$+25x−47=(−8x−3)(ax−2)−53 You should then multiply (−8x−3) and (ax−2) 24$$x^{2}$$+25x−47=−8a$$x^{2}$$−3ax+16x+6−53 Then, reduce on the right side of the equation 24$$x^{2}$$+25x−47=−8a$$x^{2}$$−3ax+16x−47 Since the coefficients of the$$ x^{2}-term have to be equal on both sides of the equation, −8a=24, or a=−3.

## Contact tutor

Send a message explaining your
needs and Hritik will reply soon.
Contact Hritik