# Tutor profile: Gaurav K.

Inactive

Gaurav K.

experience of 4 years tutoring

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## Questions

### Subject: Trigonometry

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Question:

If tan2A.tan3A=1, then find the value of ( 2cos^2 5A/2 -1)

Inactive

Gaurav K.

Answer:

Ans:- 0 tan2A.tan3A=1, then 2A+3A= 90 A=18 ( 2cos^2 5A/2 -1 )= 2 cos^2 45 -1= 2*1/2 -1 = 1-1=0

### Subject: Geometry

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Question:

If a triangle ABC with centroid G having a median AD of length 12 cm, then what would be the length of AG.

Inactive

Gaurav K.

Answer:

ANS:- AG=8 cm. since, G is centroid it divides medians in 2:1 ratio. so, length of AG= 2*length of AD/(2+1)= 2*12/3= 24/3= 8 cm. hence required length of AG= 8 cm.

### Subject: Algebra

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Question:

(Y-Z)^3 + (Z-X)^3 + (X-Y)^3 =?

Inactive

Gaurav K.

Answer:

ANS:- 3(Y-Z)(Z-X)(X-Y) IF , A+B+C=0 Then A^3+ B^3+C^3= 3ABC SO, ( X-Y)+(Y-Z)+(Z-X)=0 Then, (X-Y)^3+(Y-Z)^3+(Z-X)^3= 3(X-Y)(Y-Z)(Z-X)

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