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Tutor profile: Haleigh M.

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Haleigh M.
Inorganic Chemistry Graduate Student
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Questions

Subject: Inorganic Chemistry

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Question:

Give the oxidation state of the metal atom in the following two complexes. Explain the difference between the two compounds. [Co(NH3)5Cl]Br [Co(NH3)5Br]Cl

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Haleigh M.
Answer:

In each complex, cobalt is in the +2 oxidation state. While the complexes have the same molecular formula, the connectivity between the two differs. In the first complex, chlorine is in the primary coordination sphere with bromine lying outside of it. In the second complex, bromine is the halogen in the primary coordination sphere. This makes the two complexes structural isomers. More specifically, the two complexes are ionization isomers.

Subject: Basic Chemistry

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Question:

Explain what is meant by a buffer solution.

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Haleigh M.
Answer:

A buffer solution is a solution which is able to maintain it's pH value within a small range. This is accomplished as a buffer solution is composed of a weak acid and its conjugate weak base or of a weak base and its conjugate weak acid. If acid is introduced to the system, the weak base reacts to neutralize it. If a base is introduced into the system, the weak acid reacts to neutralize it.

Subject: Algebra

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Question:

Supposed that Alice and Taylor are walking left- to-right along a straight brick wall. At some point along the wall, they decide to race to the end. Alice takes off to the right, and Taylor runs to the left. They each reach their respective ends at the same time, 30 seconds after they began. If Alice was running 1.5 feet per second faster than Taylor and the wall is 150 ft long, how fast did each person run? At what point along the wall did they begin their race?

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Haleigh M.
Answer:

The first thing to do is solve for how fast they were running. To begin, a= alice's speed and t= taylor's speed. We know that a total of 150 feet (the length of the wall) was covered in 30 seconds of each person running. 150 = 30(a) + 30(t) Reducing this by dividing everything by 30 gives Equation 1 (1) 5 = a + t Additionally, alice's speed is equal to taylor's speed plus 1.5 ft/s. This gives us Equation 2 (2) a = t + 1.5 Plus Equation 2 into Equation 1 gives us the following equation, used to solve for taylor's speed 5 = t + 1.5 + t 5= 2t + 1.5 3.5 = 2t t = 1.75 ft/second Next, plug Taylor's speed into equation 2 a = t + 1.5 a = 1.75 + 1.5 a = 3.25 ft/second Next to solve for where the race began. We know that they were running for 30 seconds each. Therefore, multiplying each person's speed (in feet per second) by the number of seconds they ran gives us the distance covered (in feet). Taylor's distance = 1.75*30 = 52.5 ft Alice's distance = 3.25*30 = 97.5 ft Therefore, their start point was 52.5 ft along the wall, with 97.5 ft remaining.

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