TutorMe homepage

SIGN IN

Start Free Trial

Thiaza T.

Lecturer in Engineering for 3 years

Tutor Satisfaction Guarantee

Trigonometry

TutorMe

Question:

If sin θ = 0.625 and cos θ = 0.500 determine the values of cosec θ, sec θ, tan θ and cot θ

Thiaza T.

Answer:

cosec θ = 1/sin θ = 1/0.625 = 1.60 sec θ = 1/cos θ = 1/0.500 = 2.00 tan θ = sin θ/cos θ = 0.625/0.500 = 1.25 cot θ = cos θ/sin θ = 0.500/0.625 = 0.80

Calculus

TutorMe

Question:

Find the gradient of the curve y = 3x^4 − 2x^2 + 5x − 2 at the points (0, −2) and (1, 4)

Thiaza T.

Answer:

The gradient of a curve at a given point is given by the corresponding value of the derivative. Thus, since y = 3x^4 − 2x^2 + 5x − 2 then the gradient; dy/dx = 12x^3 − 4x + 5 At the point (0, −2), x = 0. Thus the gradient = 12(0)3 − 4(0) + 5 = 5 At the point (1, 4), x = 1. Thus the gradient = 12(1)3 − 4(1) + 5 = 13

Differential Equations

TutorMe

Question:

Show that y(x)=x^(-3/2) is a solution to 4x^2 (d^2 y)/(dx^2 )+12x dy/dx+3y=0 for x>0.

Thiaza T.

Answer:

Show that y(x)=x^(-3/2) is a solution to 4x^2 (d^2 y)/(dx^2 )+12x dy/dx+3y=0 for x>0. We’ll need the first and second derivative to do this dy/dx= -3/2 x^(-5/2) (d^2 y)/(dx^2 )=15/4 x^(-7/2) Plug these as well as the function into the differential equation 4x^2 (-3/2 x^(-5/2) )+12x(15/4 x^(-7/2) )+3y=0 15x^(-3/2)-18x^(-3/2)+3x^(-3/2)=0 0=0 So, y(x)=x^(-3/2) does satisfy the differential equation and hence is a solution.

Send a message explaining your

needs and Thiaza will reply soon.

needs and Thiaza will reply soon.

Contact Thiaza

Ready now? Request a lesson.

Start Session

FAQs

What is a lesson?

A lesson is virtual lesson space on our platform where you and a tutor can communicate.
You'll have the option to communicate using video/audio as well as text chat.
You can also upload documents, edit papers in real time and use our cutting-edge virtual whiteboard.

How do I begin a lesson?

If the tutor is currently online, you can click the "Start Session" button above.
If they are offline, you can always send them a message to schedule a lesson.

Who are TutorMe tutors?

Many of our tutors are current college students or recent graduates of top-tier universities
like MIT, Harvard and USC.
TutorMe has thousands of top-quality tutors available to work with you.

Made in California

© 2018 TutorMe.com, Inc.