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# Tutor profile: Mistrodda G.

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Mistrodda G.
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## Questions

### Subject:Pre-Algebra

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Question:

How to Solve Two-Step Equations 3x + 4 = 10

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Mistrodda G.

Step 1: Use the inverse (opposite) operation to solve the equation. Hint: addition is being used in the problem, so you will use subtraction to solve it. Step 2: Subtract 4 from each side. 3x + 4 - 4 = 10 - 4 Step 3: Simplify both sides. 3x (+4 -4) = (10 - 4) therefore 3x = 6 Step 4: Again, use the inverse (opposite) operation to solve the equation. Hint: multiplication is being used in the problem, so you will use division to solve it. Step 5: Divide both sides by the number that is next to your variable. 3x/3 = 6/3 Step 6: Simplify both sides. 3x/3 = x and 6/3= 2; therefore x = 2

### Subject:Basic Math

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Question:

Multiply Whole Numbers using Partial Products 523 x 18 = _______

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Mistrodda G.

Step 1: Arrange or rewrite the problem vertically. 523 x 18 Step 2: Multiply the top number (523) by the value of the digit in the ones in 18 (which is 8). 523 x 8 = 4184 Step 3: Multiply the top number (523) by the value of the digit in the tens in 18 (which is 10). 523 x 10 = 5230 Step 4: Add the partial products. 4184 + 5230 = 9,414

### Subject:Algebra

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Question:

Solve the following equation. (6 + 2p) (4 + 3p)

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Mistrodda G.

(6 + 2p) (4 + 3p) Step 1: Multiply each term in the second expression (4 + 3p) by the first term in the first expression (6). 6 x 4 = 24 6 x 3p = 18p Step 2: Multiply each term in the second expression (4 + 3p) by the second term in the first expression (2p). 2p x 4 = 8p 2p x 3p = 6p² Step 3: Add all like terms from the products. 24 + (18p + 8p) + 6p² = 24 + 26p + 6p²

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