What is the probability that two heterozygous tall pea plants will produce homozygous tall, heterozygous tall, and homozygous short offspring (tall being dominant)?
The first step to solving this problem is to create a punnett square. Once the square is completed the results should be TT, Tt, Tt, tt. This tells us that there is a 25% chance of homozygous tall pea plants, a 50% chance of heterozygous tall pea plants and a 25% chance of homozygous short pea plants.
Students in a class have grades of 87%, 67%, 94%, 83%, 74%, 83%, and 78% on the first test of the year. Find the mean, median and mode of the scores on the first test. Round to the nearest hundredth.
To find the mean add all of the scores together and divide but the number of scores provided. Added together is equals 566, then divide that by 7 and get 80.86% is the mean rounded to the nearest hundredth. The median is the middle number in the series therefore we want to line the numbers up in order from smallest to largest. We use the equation (n+1)/2 to find which number in the sequence is our median, n being the number of data values. (7+1)/2=4, therefore the 4th value is our median. 67%, 74%, 78%, 83%, 83%, 87%, 94% if we count over to the 4th value we get 83% as our median. For the mode it is the value that occurs most often in a series and 83% is the only number that appears more than once therefore 83% is your mode as well.
In order to solve this problem you must start by distributing the -3 times 2x^2+4+5x^4 and get -6x^2-12-15x^4. Then you plug that back into the equation, 12x^2-6x^2-12-15x^4+7x. the final step is to combine like terms and put the terms in the proper order. Your final answer is -15x^4+6x^2+7x-12