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Ryan R.
Freshman at Southern Methodist University
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Pre-Algebra
TutorMe
Question:

2a + a + 2= 17

Ryan R.

First we need to combine like terms. Two a's plus one a equals three a's so we now have 3a+2=17. We subtract the 2 from both sides and get 3a=15. To get a by itself we divide both sides by 3 and get a=5.

Algebra
TutorMe
Question:

What are the solutions to the equation Y = 8X^2 + 6X - 2?

Ryan R.

To find the solutions to the equation we need to find the values of X which makes Y = to 0. In order to do so we set 8X^2 + 6X - 2 equal to 0. We now need to factor the equation. If we factor the 8X^2 into 8X and X and the -2 into -2 and 1 our equation becomes (8X - 2)(X + 1) = 0. We set each side equal to 0 because if one side equals 0 the whole equation will become 0. We find that 8X-2=0 when X equals 1/4 and X+1=0 when X equals -1 so our solutions are -1 and 1/4.

Algebra
TutorMe
Question:

Jack worked at a car dealership for two and a half years. If he sold 6 cars a month, how many cars did he sell in total?

Ryan R.

First you must turn this word problem into an equation. If X is the number of months he worked for and Y is the number of cars he sold then the equation becomes 6X = Y In order to find out how many cars he sold, you must figure out how many months he worked for. If there are 12 months in a year and he worked for 2.5 years, 2.5 x 12 = 20 months. The equation is now 6 x 20 = Y, thus Jack sold 120 cars in total.

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