Determine the dimensions of the product of mass times velocity in FLT system.
mv=(W/g)v here w is the weight and we all know that w=mg so m=w/g. By substituting units into the equation we get N/(m/s^2)*(m/s) so when we cancel out the units that are the same we get N*s which in FLT we get FT (newton)*(time).
Find the derivative with respect to x of 3x^2-4x+1
ans: 6x-4 To solve this we first look at the first number with an x term in it (3x^2). To find the derivative of it the known equation is to take the 3 out in front because it is a known constant. So we have 3*(x^2) now and to solve a derivative the equation is (nx)^(n-1) where n is the power that it was first raised to. So our answer will be 3*(2x)^(2-1) which is 6x, we then use the same equation on the second component of the trinomial to get 4*(1x)^(1-1) and anything raised to the 0 power is 1 so our answer is just 4*1=4. The third component is just a number so the derivative of it is just 0. Putting our numbers together we get 6x-4.
Please factor: 4x^2-13x+3=0 and solve for x
answer: (x-3)(4x-1)=0, x=3 and x=1/4 To solve this you first must think of two numbers that when multiplied together equal 3. In this case their arent many answers all you have is 1 and 3. The second step is to factor the 4x^2. So the factorization of it will be (4x and x) or (2x and 2x). Since 2*3+2*1 wont equal to 13 the answer must be (4x and x). Putting the found numbers together we have (4x-3)(x-1) or (4x-1)(x-3) we know that they will both be negative since the b part of the trinomial is negative (ax^2+bx+c) and also since the C is positive and 2 negatives multiplied together is positive