Tutor profile: Meghana G.
What is the best strategy for handling the CARS section passages on the MCAT?
While each student's strategy should be fine-tuned to work best for them, in general, making a few notes about the main points of each paragraph in a CARS passage often proves helpful to make sure you understand the passage and in quickly referencing the relevant sections when answering the questions. I also suggest that reading the passage before reading the questions saves time and produces better results.
Subject: Java Programming
Explain the following method signature: public static void main(String args)
public: known as the access modifier, this specifies the visibility of the method. A medthod marked as public is visible to all other classes. static: This marks the method as a class method, which means that the method can be called even without a specific instance of the class. void: All methods in Java must declare their return type. Void denotes that the method is not expected to return anything. main: the name of the method. In java, execution begins with the main method. String args: the parameter passed to the main method.
A 10 kg ball is launched at at 30 degree angle from a height of 100 m. If the ball reaches its maximum height 3 seconds after it was launched, what speed was the ball originally launched at? Assume negligible air resistance.
The mass of the ball is irrelevant, as all objects fall at the same rate (g = 9.8m/s^2). A ball launched at an angle follows a parabolic path. Thus, at the maximum height, the vertical velocity is 0. We know that it took 3 seconds for the vertical velocity to become 0, at that the acceleration was -g the entire time (only gravity acts on the ball once it has been launched). Therefore, the initial vertical velocity must be 3*g = 29.4 m/s. To find the initial velocity (the vector representing both horizontal and vertical components combined), we use trigonometry. The magnitude of the velocity is 29.4/sin(30).
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