Tutor profile: Julian C.
Given the following values, calculate the hypotenuse and base of the right angle triangle. - Angle between base and hypotenuse = 51 Deg - Height of triangle = 10
Base of Triangle --- tan(51) = 10/Base --- Base=8.098=8.1 Hypotenuse--- H = 10/(sin(51)) = 13
Differentiate y = (x^3+7x-1)(5x+2)
y' = (x^3+7x-1)D(5x+2) + D(x^3+7x-1)(5x+2) = (x^3+7x-1)(5) + (3x^2+7)(5x+2) = 5x^3+35x-5+15x^3+6x^2+35x+14 = 20x^3+6x^2+70x+9
Solve the following system of equations x/3 - y/2 = 0 x + 8y = 16
We first multiply all terms of the first equation by the Least Common Multiple of 2 and 3 which is 6. 6(x/3 - y/2) = 6(0) x + 6y = 16 We then solve the following equivalent system of equations. 2x - 3y = 0 x + 6y = 16 which gives the solution x = 16-6y 2x - 3y = 0 32-12y-3y=0 y=-32/15 x=16+62/5=142/5
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