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Joy B.
Math Tutor for over 10 years
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Geometry
TutorMe
Question:

Point A is at $$(2,4)$$ and Point B is at $$(9, 11)$$ 1. Find the distance between the points 2. Find the midpoint between the points

Joy B.

1. To answer the first part we need the distance formula which is : Distance Formula $$= \sqrt{ (x_2 - x_1)^2 + (y_2-y_1)^2}$$ Next we need to assign $$(x_1, y_1) and (x_2, y_2)$$ lets assign point A to $$(x_1, y_1)$$ and point B to $$(x_2, y_2)$$ Now we can plug in our points and solve. Distance Formula$$= \sqrt{ (9 - 2)^2 - (11-4)^2}$$ $$= \sqrt{ (7)^2 + (7)^2}$$ $$= \sqrt{ 49 + 49}$$ $$= \sqrt{ 98}$$ 2. In this part we need the midpoint formula Midpoint = $$(\frac{x_1 + x_2}{2},\frac{ y_1 + y_2}{ 2})$$ Using the same points from part 1 we have: Midpoint = $$(\frac{2 + 9}{2},\frac{ 4 + 11}{ 2})$$ = $$(\frac{11}{2},\frac{ 15}{ 2})$$

C++ Programming
TutorMe
Question:

Using function overloading, 1. Write a function 'Area' which accepts a double radius and returns the area of a circle ( $$A = \pi * r^2$$ ) 2. Write another function 'Area' which accepts a double length and a double width and returns the area of a rectangle

Joy B.

double Area ( double radius) // Calculates the area of a circle { const double pi = 3.14; return pi * pow(radius, 2); //returns $$\pi * r^2$$ } double Area ( double length, double width) //Calculates the area of a rectangle { return length * width; // returns $$l*r$$ }

Algebra
TutorMe
Question:

Solve the following equation for x: $$3(x + 5) = 39$$

Joy B.

Here we want to get x by itself, to do this we need to get rid of the 3 in front of the parenthesis, we can do this one of two ways. $$3(x + 5) = 39$$ Method 1: Divide both sides by 3 parenthesis $$x + 5 = 13$$ subtract 5 from both sides $$x = 8$$ Solution!! Method 2: distribute 3 into the parenthesis $$3x + 15 = 39$$ Subtract 15 from both sides $$3x = 24$$ Divide both sides by 3 $$x = 8$$ Solution!! Choose your favorite method and solve!

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