Enable contrast version

# Tutor profile: Uddhav G.

Inactive
Uddhav G.
Prior Tutoring Experience, Student at Claremont McKenna College
Tutor Satisfaction Guarantee

## Questions

### Subject:Calculus

TutorMe
Question:

Solve the following: $$\int_2^\5 \mathrm{e}^{2x},\mathrm{d}x$$

Inactive
Uddhav G.

First integrate the expression $$e^{2x}$$, which results in $$frac{e^{2x}}{2}$$ The result has the lower bound of 2 and the upper bound of 5. (1) -- Substituting x for the upper bound results in 11,013 (2) -- Substituting x for the lower bound results in 27 Subtracting (2) from (1) -> 11,013-27 = 10,986

### Subject:English as a Second Language

TutorMe
Question:

It was a lovely, sunny afternoon. Jane _____ hard to finish her homework quickly so that she _____ go out to play. Fill in the blanks with the most suitable answers: A) worked, can B) worked, could C) works, can D) works, could

Inactive
Uddhav G.

Answer: B WORKED: past tense of WORK COULD: past tense of CAN While option C may seem reasonable, bear in mind that the first sentence sets the scene in the past.

### Subject:Economics

TutorMe
Question:

In a hypothetical situation, an economy exists for only 2 years. It produces two products in these two years: motorbikes and cars. In year 1, 1,000 motorbikes are sold at $3,000 each, and 500 cars are sold at$10,000 each. In year 2, 1,100 motorbikes are sold at $3,100 each, and 450 cars are sold at$12,000 each. a) Calculate the nominal GDP in years 1 and 2. b) Calculate the real GDP for both years, with year 1 acting as the base year. c) Work out the implicit price deflator for both years. d) What are the growth rates of real output and prices?

Inactive
Uddhav G.

a) $$NominalGDP_1 = 1,000*3,000 + 500*10,000$$ $$= 8,000,000$$ $$NominalGDP_2= 1,100*3,100 + 450*12,000$$ $$= 8,810,000$$ b) $$RealGDP_1 = 1,000*3,000 + 500*10,000$$ $$= 8,000,000$$ $$RealGDP_2= 1,100*3,000 + 450*10,000$$ $$= 7,800,000$$ c) The implicit price deflator is the given by: $$P_t^b = \frac{NominalGDP}{RealGDP}$$ Where $$t$$ is the given year, and $$b$$ is the base year $$P_1^1 = \frac{8,000,000}{8,000,000} *100$$ $$=100$$ $$P_2^1 = \frac{8,810,000}{7,800,000} *100$$ $$=112.95$$ d) The growth rate of real output, $$g^y$$, is the change in the real GDP between the years: $$g^y=\frac{7,800,000-8,000,000}{8,000,000}*100\%$$ $$g^y=-0.025 \%$$ The growth rate of real prices is simply equivalent to inflation, $$\pi$$, which can be found from the change in the implicit price deflator $$\pi=\frac{112.95-100}{100}*100\%$$ $$\pi=12.95 \%$$

## Contact tutor

Send a message explaining your
needs and Uddhav will reply soon.
Contact Uddhav