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Gretchen C.

Teacher, Tutor, Program Director

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Linear Algebra

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Question:

Solve the following matrix. [4 2] [3] 3 1 2

Gretchen C.

Answer:

First, think of the matrix as two problems. (3) [4] and (2) [2] 3 1 Then, solve each problem. (3)(4) = 12 (3)(3) = 9 (2)(2) = 4 (2)(1) = 2 Represent the answers in the appropriate order of the matrix. [12 4] 9 2

Pre-Algebra

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Question:

In one day, about c + 120 billion red blood cells are created and destroyed. How many red blood cells would be created and destroyed in one day if c = 53 billion?

Gretchen C.

Answer:

If c = 53 billion, then let's plug it into the equation. 53 billion + 120 billion = 173 billion Therefore, c = 173 billion red blood cells.

Algebra

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Question:

The basketball team decides it wants to do a fundraiser. They decide to sell snacks at their games. They determined that the initial set up cost could be represented by the equation y = 1/2x + 3. Write a scenario that would describe the set up cost as defined by this equation. Then, determine how many snacks would have to be sold to make a profit of $45.00.

Gretchen C.

Answer:

In this equation the slope is 1/2 (the number attached to the x variable) and the y-intercept is 3. In the context of this equation, it could mean that it would cost $3.00 to buy supplies to sell the snacks. After this initial cost of $3.00, for every one dollar sold on a snack, the team would collect $2.00. If a profit of $45.00 was desired, we would plug in $45.00 for the y-variable to get this equation. 45 = 1/2x + 3 To solve the equation, first subtract 3 from both sides of the equation. 45 (-3) = 1/2x + 3 (-3) 42 = 1/2x Then, to get the x-variable alone, multiply both sides by 2. (2) 42 = 1/2x (2) 84 = x In order for the basketball team to make $45.00 in their fundraiser, they must sell 84 snacks.

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