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Tutor profile: Kritika K.

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Kritika K.
Student at BITS Pilani, Research Assistant (BioChemical), 4 years tutoring experience
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Questions

Subject: SAT II Chemistry

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Question:

What types of bonding can be found in a sample of Liquid Water? A. Nonpolar Covalent Bonds only. B. Both Polar Covalent and Hydrogen Bonds. C. Metallic and Ionic Bonds D. Hydrogen Bonds. E. Ionic and Nonpolar Hydrogen Bonds.

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Kritika K.
Answer:

Option B is the correct answer. The water molecule consists of two hydrogen and one oxygen atom. Oxygen is more electronegative than Hydrogen. This difference in electronegativity pulls the bonded pair of electrons towards it, making the covalent bond polar, the oxygen atom partially negative and the hydrogen atom partially positive. Furthermore, the partially positive hydrogen atom of one molecule is attracted to the partially negative oxygen atom of another molecule.This creates a force of attraction between two separate molecules. This attractive force is also known as a hydrogen bond.

Subject: Biology

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Question:

Consider the allele for an eye spot in cats to be recessive and the allele for having no spot around the eye to be dominant. If both the mother and father at heterozygous, what is the possibility of the offspring having a spot around the eye?

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Kritika K.
Answer:

Consider the allele for having NO spot around the eye be = A (dominant) Consider the allele for having spot around the eye be = a(recessive) Given that both parents are heterozygous which means they have one of each allele Male parent = (Aa) Female parent= (Aa) Forming the punnet square: A a A. AA. Aa a. Aa. aa The offspring will have a spot around the eye if it is (aa) (homozygous recessive) The possibility for the same is 1 in 4 Hence, the possibility is 25%.

Subject: Calculus

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Question:

Integrate the following : ∫ 3x^2 sin(x^3 + 1) dx.

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Kritika K.
Answer:

Considering that the term inside the sine function has an order of 3 and term with the dx is of order 2, Take (x^3+1) as a variable, u u= x^3+1 du= 3x^2 dx So, the function is now ∫sin(u) du Integration of sine function = - cos function Hence, ∫sin(u) du = -cos(u) + constant Substituting, ∫ 3x^2 sin(x^3 + 1) dx = -cos(x^3 + 1) + k

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