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# Tutor profile: Gaurav M.

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Gaurav M.
Tutor for 3 years
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## Questions

### Subject:Physics (Newtonian Mechanics)

TutorMe
Question:

There is a solid box (M= 5kg) on the floor. there is a guy who is pulling this box with the help of A string from top. Find out how much force required to lift this box.

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Gaurav M.

As we know m=5kg There will be only one force in freeform i.e. gravitational force of Earth. Mg = 5g When someone will pull up this box then there will be to forces One is gravitational and another is in opposite direction due to man (let's say it F) So when F=Mg Then box will lift up . F should be more than 5gN.

### Subject:Geometry

TutorMe
Question:

For two right angle triangles find out the ratio of their heights. if ratio of their area's is 1:4 and ratio of their of their base are 1:2 .

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Gaurav M.

Here, there are two right angle triangles(RAT) . There's ratio of area and base has given. Area of a triangle = 1/2*height of triangle*base of triangle A1= 1/2×H1×B1 A2=1/2×H2×B2 Let's find out the ratio A1/A2= H1.B1/H2.B2 1/4=H1.1/2.H2 SO, H1/H2=1/2

### Subject:Basic Math

TutorMe
Question:

Solve for x : 6x+20-15/3*(2-1)2=22

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Gaurav M.

Here we will follow BODMAS Rule :- according to which in these types of questions first we should solve the bracket then division and then multiple and then addition and subtraction. So here: 6x+20-15/3*(1)2=22 6x+20-5*2=22 6x+20-10=22 6x+10=22 6x=12 X=12/6=2

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