Subjects
PRICING
COURSES
SIGN IN
Start Free Trial
Chandrakanth R.
Final Year Engineering Student at VIT University,INDIA
Tutor Satisfaction Guarantee
Trigonometry
TutorMe
Question:

Show that 1 + tan^2(x) = sec^2(x)

Chandrakanth R.
Answer:

tan^2(x) + 1 = sin^2(x)/cos^2(x) + 1 = [sin^2(x) + cos^2(x)]/cos^2(x) = 1/cos^2(x) = (1/cos(x)^)2 = sec^2(x) Thus tan^2(x) + 1 = sec^2(x).

Basic Math
TutorMe
Question:

10^(2y) = 25, then 10^(-y) equals:

Chandrakanth R.
Answer:

Rewriting the given expression 10^(2y) = 25 (10^y)^2 = 25 10^y = 5 1/10^y = 1/5 10^(-y) = 1/5

Algebra
TutorMe
Question:

For what value of the constant K does the equation Kx^2 + 2x = 1 have two real solutions?

Chandrakanth R.
Answer:

1.Rewrite the given quadratic equation in standard form: Kx^2 + 2x - 1 = 0 2.Discriminant = 4 - 4(K)(-1) = 4 + 4K 3.For the equation to have two real solutions, the discriminant has to be positive. Hence we need to solve the inequality 4 + 4K > 0. 4.The solution set to the above inequality is given by: K > -1 for which the given equation has two real solutions.

Send a message explaining your
needs and chandrakanth will reply soon.
Contact chandrakanth
Ready now? Request a lesson.
Start Session
FAQs
What is a lesson?
A lesson is virtual lesson space on our platform where you and a tutor can communicate. You'll have the option to communicate using video/audio as well as text chat. You can also upload documents, edit papers in real time and use our cutting-edge virtual whiteboard.
How do I begin a lesson?
If the tutor is currently online, you can click the "Start Session" button above. If they are offline, you can always send them a message to schedule a lesson.
Who are TutorMe tutors?
Many of our tutors are current college students or recent graduates of top-tier universities like MIT, Harvard and USC. TutorMe has thousands of top-quality tutors available to work with you.