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Tutor profile: Jasmine A.

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Jasmine A.
student of mathematics at the University of Manchester
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Questions

Subject: Trigonometry

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Question:

complete the following trig identity: sin2x = ?

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Jasmine A.
Answer:

sin2x = 2sinxcosx

Subject: Basic Math

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Question:

Divide 471 by 3

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Jasmine A.
Answer:

There are multiple methods that can be used for long division. One of which is 'chunking'. 471 -300 (3x100) =171 -150 (3x50) =21 -21 (3x7) =0 then add together the multiples of 3 used: 100+50+7= 157 so 157 is the answer.

Subject: Algebra

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Question:

Make y the subject of the following equation: 3x/(y+1) = 4x^2

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Jasmine A.
Answer:

First step is to multiply out any fractions in the equation. In this case that involves multiplying every term by (y+1) giving us: 3x = 4x^2 x y + 4x^2 Next we separate the variables, keeping every term that involves y on one side of the equals sign: 3x - 4x^2 = 4x^2 x y Then we need to factorise y out of the right hand side of the equation: 3x - 4x^2 = y(4x^2) and finally divide by 4x^2 to leave y on its own as the subject of the equation: y = (3x - 4x^2)/(4x^2) this can also be simplified to y = 3/4x - 1

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