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Tutor profile: Mihir S.

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Mihir S.
Tutor for the past two years in Computer Science and present intern at WAT Consult.
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Questions

Subject: Calculus

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Question:

Find the limit of the following expression when the value of x tends to 0. Expression= ( xlnx ) It can be written as lnx/(1/x)

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Mihir S.
Answer:

It can be written as lnx/(1/x) where numerator is lnx and denominator is 1/x. Now on substituting the value of x, the expression becomes a form of (inf)/(inf) and hence, we have to apply L'Hospitals rule. It states, when we calculate the limit value of an expression, if it turns out to be of the form 0/0 or inf/inf, then differentiate the numerator and denominator respectively and then substitute the value. So, applying L'Hospitals Rule on the given expression, differentiating lnx and 1/x respectively, numerator becomes 1/x and denominator becomes -1/x^2. Simplifying the numerator/denominator expressions, we get the new expression as -x, now substitute the value of x=0, thus the limit to the above expression is 0.

Subject: C++ Programming

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Question:

Explain the concept of functional overloading in C++

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Mihir S.
Answer:

Function overloading is a feature in C++ where two or more functions can have the same name but different parameters. Consider the following code snippet as an example:- void polyf(int i) { cout << " Here is int " << i << endl; } void polyf(double f) { cout << " Here is float " << f << endl; } void polyf(char* c) { cout << " Here is char* " << c << endl; } So, for the same name 'polyf', different function definitions can be derived which differs in parameters.

Subject: C Programming

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Question:

Suppose you have to swap the contents of two variables. How would you implement and write a pseudo code for the same.

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Mihir S.
Answer:

To swap two variables, the idea is to consider a third variable that will temporarily hold the value of the first variable so that it's value doesn't get lost when it has been assigned a value of the second variable. So, if we have variables a and b, consider a variable temp, assign it to the value of a. Now, copy the contents of b to a and that of temp to b. You will have the numbers swapped. Pseudo Code: { temp=a; a=b; b=temp; }

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