José S.

Tutored throughout college, Researcher

Tutor Satisfaction Guarantee

Calculus

TutorMe

Question:

$$ \int \frac{x} {(x+2)^2} dx $$

José S.

Answer:

First we use partial fractions to simplify the integral $$ \frac{x}{(x+2)^2} = \frac{A}{x+2} + \frac{B}{(x+2)^2} $$ $$ x = A(x+2) + B $$ $$ x = Ax + 2A + B $$ For all x terms $$ x = Ax$$ $$A = 1$$ For all constant terms $$0 = 2A + B$$ $$ B = -2$$ So, our integral can now be expressed as $$ \int \frac{1}{x+2} - \frac{2}{(x+2)^2} dx$$ which can be solved to obtain $$ \ln{|x+2|} + \frac{2}{x+2} + C $$

Chemical Engineering

TutorMe

Question:

What would be the more preferred method of separation for proteins and cells? Explain your reasoning a. Distillation b. Absorption/Stripping Column c. Membrane separation d. Leaching e. Liquid-Liquid Extraction

José S.

Answer:

c. Membrane Separation Protein and microorganism separation is a temperature-sensitive process, which rules our the use of distillation. Furthermore, one would need to take special considerations when adding a material separating agent since these could also change the nature of the product to be separated, so absorption, leaching, and LLE are ruled out. Therefore, it is better to conduct these types of separations using membrane separation processes. Proteins can also be separated effectively using chromatography.

Physics

TutorMe

Question:

How much heat is required to raise the temperature of a kilogram of gold from 0C to room temperature (25C)? The heat capacity of Gold is 0.129 J/g/C

José S.

Answer:

In order to calculate heat, we utilize the equation Q = mc(T_f - T_i) Where m = mass c = heat capacity T_f = final temperature I_i = initial temperature Since heat capacity was given in J/g/C, we will use 1000g gold as our mass Q = 1000g X 0.129 J/g/C X (25C - 0C) Q = 1000g X 0.129 J/g/C X 25C Q = 3225J So, 3225 Joules of energy is required to raise the temperature of 1kg of gold from 0 to 25C

Send a message explaining your

needs and José will reply soon.

needs and José will reply soon.

Contact José

Ready now? Request a lesson.

Start Session

FAQs

What is a lesson?

A lesson is virtual lesson space on our platform where you and a tutor can communicate.
You'll have the option to communicate using video/audio as well as text chat.
You can also upload documents, edit papers in real time and use our cutting-edge virtual whiteboard.

How do I begin a lesson?

If the tutor is currently online, you can click the "Start Session" button above.
If they are offline, you can always send them a message to schedule a lesson.

Who are TutorMe tutors?

Many of our tutors are current college students or recent graduates of top-tier universities
like MIT, Harvard and USC.
TutorMe has thousands of top-quality tutors available to work with you.