Enable contrast version

# Tutor profile: Nick B.

Inactive
Nick B.
Engineering Teaching Assistant at Ohio State
Tutor Satisfaction Guarantee

## Questions

### Subject:Pre-Algebra

TutorMe
Question:

What is the volume of a box whose length is 10 feet, width is 4 feet, and height is 5 feet?

Inactive
Nick B.

The first thing I ask myself when answering a question is "what is this question asking for?" In this case, I can see that it is asking for the volume of a box. This leads me to my next set of questions, which are "what additional information does this question give me" and "what is the equation for the volume of a box?" What the Question is Asking: Volume of a box Volume Equation for a box: Length x Width x Height Given Information: Length is 10 feet, width is 4 feet, and height is 5 feet. Answer: Plug in your given information into the equation Volume = 10 feet x 4 feet x 5 feet Volume = 200 ft^3

### Subject:Calculus

TutorMe
Question:

Find the derivative of d/dx ( sin (4x) + 2x^2)

Inactive
Nick B.

The easiest way to look at this problem is to look at it as two separate derivatives added together, like this: We now solve for both of these derivatives separately. We will first look at d/dx (sin(4x)) When deriving trig functions, it is important to note that the differential rule is applied here. This means that you have to derive the trig function and the inside separately and multiply together, like this: d/dx (sin(4x)) * d/dx (4x) When deriving the trig function of sin(4x), it is best to pretend the (4x) is not even there and just focus on what the derivative of sin is. We know from trig properties that the derivative of sin is cos, so we can solve this portion of the differential. d/dx (sin(4x)) = cos(4x) Now look at the second part of this and see the d/dx (4x) and solve for it. When looking at derivatives for a single power, the derivative is simply the number in front of the X. In this case it is 4. d/dx (4x) = 4 Now plug these two answers into the equation: d/dx(sin(4x)) * d/dx(4x) cos(4x) * 4 4cos(4x) <---- This is the answer to the first portion! Now we have to look at the second portion of this problem and that is the d/dx (2x^2). The best way to look at this problem is by bring the 2 to the front of the equation to make it: 2* d/dx (x^2). Now solve for d/dx (x^2).This uses the power rule which is [x^n]' = [nx^(n-1)]. In simpler terms, we have x^2 in this problem, so we bring the power of 2 in front of the equation and subtract the 2 by 1. This will make it 2x^1, or simply 2x. Plug this back into the equation of 2 * d/dx (x^2). 2 * (2x) =4x Final Step! Plug your answers for each portion into the original equation: d/dx (sin(4x)) + d/dx (2x^2) = 4cos(4x) + 4x (Final Answer! :D)

### Subject:Algebra

TutorMe
Question:

Solve the quadratic equation for X: x^2 - x - 12 = 0

Inactive
Nick B.

## Contact tutor

Send a message explaining your
needs and Nick will reply soon.
Contact Nick

Start Lesson

## FAQs

What is a lesson?
A lesson is virtual lesson space on our platform where you and a tutor can communicate. You'll have the option to communicate using video/audio as well as text chat. You can also upload documents, edit papers in real time and use our cutting-edge virtual whiteboard.
How do I begin a lesson?
If the tutor is currently online, you can click the "Start Lesson" button above. If they are offline, you can always send them a message to schedule a lesson.
Who are TutorMe tutors?
Many of our tutors are current college students or recent graduates of top-tier universities like MIT, Harvard and USC. TutorMe has thousands of top-quality tutors available to work with you.
BEST IN CLASS SINCE 2015
TutorMe homepage