Tutor profile: Arsalan K.

An oil cooler in a high-performance engine has an outside surface area $$ 0.12 m^2$$and a surface temperature of 65 degree Celsius. At any intermediate time air moves over the surface of the cooler at a temperature of 30 degree Celsius and gives rise to a surface coefficient equal to 45.4 $$ W/ m^2 K$$. Find out the heat transfer rate?

Since, Area(A) =$$ 0.12 m^2$$ T1=30 degree celcius T2=65 degree celcius h=45.4 $$ W/ m^2 K$$ Q = (T2 – T1) A h Q = 0.12 (65-30) 45.4 = 190.68 W

Find the integral of f(x)= (sin x)(cos x)^2

let y=cosx therfore dy=-sinxdx so, $$\int_{a}^{b} f(x) dx$$=$$\int_{a}^{b} -y^2 dy$$ $$\int_{a}^{b} f(x) dx$$=$$-y^3/3 + c$$ $$\int_{a}^{b} f(x) dx$$=$$-(cosx)^3/3 + c$$

My mother's age is three times my age. The sum of our ages is 40. How old am I? How old is my mom?

Let x=my age y=mom age So, Given y=3x -----eq1 also x+y=40-----eq2 putting the value of y from eq1 into eq2 x+3x=40 4x=40 x=10 years-----(my age) putting the value of x in eq1 y=3*10 y=30 years----(mom age).