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# Tutor profile: Hannah D.

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Hannah D.
Tutor for 6 years
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## Questions

### Subject:Pre-Calculus

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Question:

Find the domain of the function f(x)=x^2 +4/ x^2 +3x+2

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Hannah D.

To find the domain find where x cannot answer 0. so set the bottom half of the equation equal to zero and solve. x^2 + 3x+ 2=0. Isolate the X's to the left side of the problem to do so subtract 2 from 0. x^2 +3x = -2. then simplify the left sid eof the equation by removing an x. so you then get x(x+3)=-2. Now treat this problems as separate equations. So x=-2 and x+3=-2 so x=2 and x=-1.

### Subject:Calculus

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Question:

For the problem perform the indicated function evaluations, f(x)=3-5x-2x^2, f(-4x)

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Hannah D.

To find the answer plug in -4x where x is in the equation. f(x)= 3-5(-4x)-2(-4x)^2. Remember PEMDAS, so first square (-4x) so to do so you multiple (-4x) times (-4x). which you get 16x^2. Put that back into the equation so you get f(x)= 3-5(-4x)-2(16x^2). now simplify the equation. and 3 - -5 times -4x -2 times 16x^2. so you get f(x)= 3+20x-32x^2

### Subject:Algebra

TutorMe
Question:

-3+2x=11, solve for x.

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Hannah D.

First, isolate the 2x by itself on one side. So move the -3 over to the right side of the equation, to do so, add 3 to 11. So now your new equation is 2x=14. then isolate the x by its self, so divide 14 by 2 to get x=7. to check your work plug 7 back into the equation. -3+2(7)=11 or -3+14=11 or 11=11

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