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# Tutor profile: Tacorria D.

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Tacorria D.
Tutor for 9 years, Middle School Math Teacher
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## Questions

### Subject:Pre-Algebra

TutorMe
Question:

Given x=5 Solve the following problem. 2x + 2 = ?

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Tacorria D.

Substitute your values in to find the answer. 2x + 2 = ? We know x = 5 2 ( 5 ) + 2 = ? 10 + 2 = 12 The Solution is 12.

### Subject:Basic Math

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Question:

What is the solution to this problem 3+5-7(4+2)?

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Tacorria D.

Solving this problem you use PEMDAS (Please Excuse My Dear Aunt Sally) In the order listed. P= Parenthesis E= Exponent M= Multiplication D= Division A= Addition S= Subtraction *If the problem only has multiplication and division left, those operations must be done from left to right no matter the order. *If the problem only has addition and subtraction left, those operations must be done from left to right no matter the order 3+5-7(4+2) First (4+2)=6 We have 3+5-7(6) Next 7*6= 42 We have 3+5-42 Lastly 3+5=8 8-42= -34

### Subject:Algebra

TutorMe
Question:

Solve for x. 3x+9-2x=27

Inactive
Tacorria D.

To begin I would combine my like terms (what are like terms?) Like terms are numbers that have the same variables (x or y) attached to them. My like terms in this problem is 3x and -2x. I also have like terms of 9 and 27. So 3x - 2x = 1x OR x. Now the problem is x+9=27. I have to do the inverse operation (+ changes to - OR - changes to positive OR multiplication changes to division and vice versa) to get the +9 on the side with its like term. +9 changes to -9 on both sides. A +9 - 9 = 0, so that cancels out and leaves us x=27-9. When we solve x=18.

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