Chi N.

2 years tutor experience, mathematics major at Texas A&M University

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Pre-Calculus

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Question:

Solve the system of linear equations by the substitution method. 4x - 3y = 5 x + 4y = -13

Chi N.

Answer:

To avoid fractions, solve the second equation for x: x + 4y = -13 => x = -4y -13. space Substitute -4y -13 for x in the first equation: 4(-4y -13) - 3y = 5 space Simplify and solve this linear equation -16y -52 -3y = 5 => -16y -3y = 5 +52 -19y = 57 => y = - 57/19 = -3. space Replace y with -3 x = -4y -13 = -4(-3) -13 = 12 -13 = -1. space The solution is (-1, -3). space Checking solution: 4x - 3y = 4(-1) - 3(-3) = -4 + 9 = 5 x + 4y = -1 + 4(-3) = -1 - 12 = -13.

Calculus

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Question:

Use the definition of the derivative to find the derivative of the following functions. V= 3 - 14(t)

Chi N.

Answer:

Slove: V= -14

Algebra

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Question:

Solve the following system of equations: -x/2 + y/3 = 0 x + 6y = 16

Chi N.

Answer:

We first multiply all terms of the first equation by the LCM of 2 and 3 which is 6. 6(-x/2 + y/3) = 6(0) x + 6y = 16 We then solve the following equivalent system of equations. -3x + 2y = 0 x + 6y = 16 which gives the solution x = 8/5 and y = 12/5

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