TutorMe homepage

SIGN IN

Start Free Trial

John F.

Math, Science, Business Tutor

Tutor Satisfaction Guarantee

HTML Programming

TutorMe

Question:

What is HTML and how is it used?

John F.

Answer:

HTML stands for Hypertext Markup Language and it is a robust, yet simple language that allows any web connected device to send, interpret, and display information. If you are looking to pursue a career as a web developer or just want to build a website in your free time HTML/CSS is the place to start!

Computer Science (General)

TutorMe

Question:

FUNCTION BASICS: Write a function to find and return the length of a line, given two coordinate points.

John F.

Answer:

The following answer uses Python syntax. ##Take as input 4 numbers: two x-coordinates, two y-coordinates def line_length(x1, y1, x2, y2): ##Use the formula length = square root((x1 - x2)^2 + (y1 - y2)^2) length = (int(x1)-int(x2))**2 + (int(y1)-int(y2))**2 length = math.sqrt(length) ##return length as a float return length

Calculus

TutorMe

Question:

Consider a rectangular bathtub whose base is 18ft^2. How fast is the water level rising if the tub fills up at a rate of 0.7 ft^3/min?

John F.

Answer:

To answer this question, it is best to first draw a rectangular prism and set the base equal to 18 ft^2. We do not know the height, nor do we need to. To solve this problem follow these steps: 1. Write down the equation for volume a rectangular prism V = b * h Fill in the variables we have values for. In this case we know the base is 18 ft^2. V = 18h 2. Take the derivative of the volume equation dV/dt = 18dh/dt The derivative of V is dV/dt and the derivative of h is dh/dt. A derivative is a "rate of change" by definition. With this in mind, the derivative of V is the rate at which the volume of water in the tub is increasing. So dV/dt is 0.7 ft^3/min. The equation is now: 0.7 = 18(dh/dt) 3. Isolate dh/dt (the rate at which the water level is increasing) by dividing both sides by 18. This gets you: 1/18(0.7) = dh/dt. 4. Solve! 1/18(0.7) = 0.039 ft/second

Send a message explaining your

needs and John will reply soon.

needs and John will reply soon.

Contact John

Ready now? Request a lesson.

Start Session

FAQs

What is a lesson?

A lesson is virtual lesson space on our platform where you and a tutor can communicate.
You'll have the option to communicate using video/audio as well as text chat.
You can also upload documents, edit papers in real time and use our cutting-edge virtual whiteboard.

How do I begin a lesson?

If the tutor is currently online, you can click the "Start Session" button above.
If they are offline, you can always send them a message to schedule a lesson.

Who are TutorMe tutors?

Many of our tutors are current college students or recent graduates of top-tier universities
like MIT, Harvard and USC.
TutorMe has thousands of top-quality tutors available to work with you.

Made in California

© 2019 TutorMe.com, Inc.