You are walking down a city street in Norway, walk past a Norwegian, and say "hello" to him. What is the most likely reaction. A. He says "hello" back, and keeps walking. B. He doesn't understand what "hello" means, because he doesn't speak English, and keeps walking. C. He looks at you confused, unsure if you were talking to him, and doesn't really know how to react.
The most likely reaction, is option C. Most Norwegians are decent in English, as they have been taught the language in school, but they aren't used to strangers saying hello to them other on the street. The Norwegian would probably look confused because it's not a situation he's used to, and he might not know how to react. Norwegians are very friendly with people they know, but tend to stay away from greeting strangers.
Solve the set of equations: 1. 3x+3y=6 2. 3x+5=-4y
We can see that both equations has the variable 2x, and we can therefore subtract equation 2 from equation 1. 3x+3y-(3x+5)=6-(-4y) 3x+3y-3x-5=6+4y 3y-5=6+4y y=-11 We can then solve the first equation. 3x+3*(-11)=6 3x-33=6 3x=39 x=13 We check our answer by checking if these values work in the second equation 3*(13)+5=-4*(-11) 39+5=44 The answer is correct.
If a ball uses 10 seconds to fall to the ground on Earth, given that the initial velocity is 0, how long will it take for the ball to fall to the ground on the Moon if it was dropped from the same height. The gravity on Earth is 9.81m/s^2 and the gravity on the Moon is 1.62m/s^2.
We start by finding out what information we have been given in the question. We have been given the time the ball takes to land on earth, and the acceleration and the starting velocity for both scenarios. We begin by finding the distance. For this, we use the formula s=ut+½at² Earth: u=0m/s, t=10s, a=9.81m/s² s=0.5*9.81m/s²*(10s)²=490.5m This is the height the ball is dropped from, and we can use this to find the time it takes for the ball to hit the ground on the moon. Moon: s=ut+½at² u=0m/s, a=1.62m/s², s=490.5m t²=2s/a t=root(2s/a) t=root(2*490.5m/1.62m/s²)≈25s