Venkat A.

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Physics (Newtonian Mechanics)

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Question:

A block of mass 50 kg is pulled by a rope of length6 m on a surface by a force of 106 N applied at the other end. If the linear density of the rope is 0.5kg/m. the force acting on 50 mass is.......

Venkat A.

Answer:

Mass of the rope is m=Linear density *length of the rope=(0.50 kg/m)(6 m )= 3 kg The total mass is M=(50 kg)+(3 kg)=53 kg. According to Newton's second law, the acceleration of the system is a=F/m=(106 N)/(53 kg)=2 m/s^2 So the force acting on the rope is Fnet = (50 kg)(2 m/s^2)= 100 N

Physics (Electricity and Magnetism)

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Question:

Calculate the wavelength for the following examples of sinusoidal electromagnetic radiation. radio, 1044 kilohertz m television, 107 megahertz m

Venkat A.

Answer:

For radio waves: The wavelength of radio waves is Lamda=c/f Here c is the speed of light(Its value is 3*10^8 m/s) and f is the frequency. So, Lamda= (3*10^8 m/s)/(1044*10^3 Hz)=287 m ------------------------------------------------------------------------------------------------------------------ For television: The wavelength of radio waves is Lamda=c/f Here c is the speed of light(Its value is 3*10^8 m/s) and f is the frequency. So, Lamda= (3*10^8 m/s)/(107*10^6 Hz)=2.803 m

Physics

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Question:

A truck of mass 2500-kg is traveling at a constant speed of 56.0 km/h when the driver removes his foot from the gas pedal. The speed of the truck 22.0 seconds later is 33.0 km/h. What is the magnitude of the average net force acting on the truck during the 22.0 s interval?

Venkat A.

Answer:

Given data Mass of truck is m=2500 kg Initial speed of truck is v0= 56.0 km/h=15.6 m/s Final speed is v=33.0 km/h= 9.17 m/s Time t=22.0 s ------------------------------------------------ Acceleration of truck is a=(v-v0)/t=( 9.17 m/s-15.6 m/s)/(22.0s)= - 0.29 m/s^2 According to Newton's second law, the net force acting onthe truck is F=ma=(2500 kg)(- 0.29 m/s^2)= -731 N So the magnitude of the average net force acting on the truck is F= 731 N

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