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Tutor profile: Joseph H.

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Joseph H.
Tutor for four years
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Questions

Subject:Pre-Algebra

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Question:

Solve following polynomials: Given x^2+3x-7 let x= -2

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Joseph H.

Substitute x in given polynomials with -2. (-2)^2 + 3(-2) - 7, which equates to 4 -6 -7 = -9

Subject:Basic Math

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Question:

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Joseph H.

First, get the least common denominator (LCD) of 3 and 4, which will be 12. For 1/3, I need to multiply 4 by numerator and denominator to get the LCD: (1*4) / (3*4) = 4/12 For 5/4, I need to multiply 3 by numerator and denominator to get the LCD: (5*3) / (4*3) = 15/12 Now I can add this two fraction with the same denominator together: 4/12 + 15/12 = 19/12

Subject:Algebra

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Question:

Linda walked for 2 hours then ran for 1 hour. If she runs three times as fast as she walks and the total trip was 20 kilometers, then how fast does she run?

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Joseph H.

Let x be the walking speed. 3x will be the running speed. 2 hours * (x) will be the distance walked and 1 hour * (3x) will be the distance run. Total distance is 20 km. Therefore, 2x+3x=20. Then 5x=20. x = 4 km/hr , 3x = 12 km/hr and it is the speed of Linda when running.

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