X^3 * X^3
When multiplying, in reality the addition rule is being applied so 3+3=6 The answer is X^6
(7x8) + 3
First the information in the parenthesis must be done: 7x8 = 56 then 3 could be added making the total: 59
If 1.35kg of Na2CO3 is treated with excess amount of Ca(OH)2, what is the amount (in g) of NaOH that can be produced?
First, the balanced equation must be produced: 1Na2CO3 + 1Ca(OH)2 --> 2NaOH + 1 CaCO3 Then the molar mass of the values needed must be found and calculated based on the periodic table: 105.99g/mol Na2CO3 and 40.00g/mol NaOH Then calculate 1.35kg Na2CO3 x (10^3g/1kg) x (1mol Na2CO3/ 105.99 g Na2CO3) x (2 mol NaOH/ 1 mol Na2CO3) x (40.00 g NaOH/ 1 mol NaOH)= 1018.964 g NaOH Last, significant figures must be in place and therefore the answer is: 1.02x 10^3 g NaOH