Enable contrast version

# Tutor profile: Abdulkareem F.

Inactive
Abdulkareem F.
Mechanical Engineer Junior at University of California, Irvine
Tutor Satisfaction Guarantee

## Questions

### Subject:Physics (Newtonian Mechanics)

TutorMe
Question:

A 3.00-kg crate slides down a ramp. The ramp is 1.00 m in length and inclined at an angle of 30.08. The crate starts from rest at the top, experiences a constant friction force of magnitude 5.00 N, and continues to move a short distance on the horizontal floor after it leaves the ramp. -Use energy methods to determine the speed of the crate at the bottom of the ramp.

Inactive
Abdulkareem F.

Because vi= 0, the initial kinetic energy of the system when the crate is at the top of the ramp is zero. If the y coordinate is measured from the bottom of the ramp (the final position of the crate, for which we choose the gravitational potential energy of the system to be zero) with the upward direction being positive, then yi = 0.500 m. 1- Write the expression for the total mechanical energy of the system when the crate is at the top: Ei = Ki + Ui = 0 + Ui = m*g*yi 2- Write an expression for the final mechanical energy: Ef = Kf+ Uf = 0.5*m*[(vf)^2] + 0 3- Use conservation of Energy Law: E(mech)= Ef - Ei = 0.5*m*[(vf)^2] - m*g*yi 4- Solve for vf: vf = [(2/m)*(m*g*yf-f*d)]^0.5 5- Substiture numerical values to get the answer: vf = 2.54 m/s

### Subject:Pre-Calculus

TutorMe
Question:

Solve the equation : sin^2(β) + sin(β) = 0 for 0≤β≤2π

Inactive
Abdulkareem F.

sin^2(β) + sin(β) = 0 sin(β)* (sin(β)+1) =0 Therefore: sinβ=0 --> β=0 or β=π OR sinβ = -1 --> β= 3π/2

### Subject:Calculus

TutorMe
Question:

Find a pair of solutions to the equation below: y'' + 5y' - 6y = 0

Inactive
Abdulkareem F.

The auxiliary equation associated with the equation: y”+5y’-6y=0 is: R^2 + 5R - 6=0 (R-1) (R+6)=0 Therefore, the roots of the previous equation are: R=1 and R=-6 Finally, the solutions of the second order differential equation are: R1= e^t R2= e^-6t

## Contact tutor

Send a message explaining your
needs and Abdulkareem will reply soon.
Contact Abdulkareem

Start Lesson

## FAQs

What is a lesson?
A lesson is virtual lesson space on our platform where you and a tutor can communicate. You'll have the option to communicate using video/audio as well as text chat. You can also upload documents, edit papers in real time and use our cutting-edge virtual whiteboard.
How do I begin a lesson?
If the tutor is currently online, you can click the "Start Lesson" button above. If they are offline, you can always send them a message to schedule a lesson.
Who are TutorMe tutors?
Many of our tutors are current college students or recent graduates of top-tier universities like MIT, Harvard and USC. TutorMe has thousands of top-quality tutors available to work with you.
BEST IN CLASS SINCE 2015
TutorMe homepage