If a football player is paid $20,000,000 to play 16 regular season games, a) How much is the player being paid per game? b) How much is the player getting paid per minute if we assume all games are 60 minutes long?
Part a). Since the player is getting paid $20,000,000 to play all 16 games, we must divide $20,000,000 by 16 games to determine the amount the player is paid per game. Therefore, $20,000,000 / 16 games = $1,250,000 per 1 game. Part b). We know that the player is being paid $1,250,000 per game and that each game is 60 minutes long. If we apply the same concept used in Part a), then we will want to divide the amount per game by the number of minutes per game. Therefore, $1,250,000 / 60 minutes = approximately $20,833 per minute is what the player is being paid.
If a cylindrical rod made from steel (yield strength of 210 MPa) with a diameter of 10 mm. Find the tension force applied that will cause the rod to yield if the other end is completely fixed.
The average stress can be determined using the equation Average Stress = Internal Force / Cross Sectional Area. We rearrange the equation to get the Internal Force = Average Stress * Cross Sectional Area. Therefore, F = (210MPa)(pi/4*(0.01m)^2) = approximately 1650 Newtons. Then by drawing a FBD, we can see that the internal force will equal the external force. Therefore, an external force of 1650 N will cause to rod to yield.
A ball is launched straight up in the air with an initial velocity of V = 20 m/s. Determine the maximum height of the ball.
First, we must apply recall the kinematic equations: 1) v_f = v_o + a*t, 2) y_f = y_o + v_o*t +1/2*a*t^2, and 3) (v_f)^2 = (v_o)^2 + 2*a*(x_f - x_o). We need to determine the time it takes the ball to reach it's maximum height which is when the velocity is equal to zero. At this time, the ball will change directions and begin traveling back in the downward position. Assuming gravitation acceleration to be -10 m/s^2, the time for the ball to reach it's maximum height can be solved with Equation 1). t = -20/-10 = 2 seconds. Then we can use Equation 2) to determine the height at t = 2 seconds. This means y_f = 20*2 +1/2*(-10)*2^2 = 40 - 20 = 20 meters. Therefore, the maximum height the ball will travel is approximately 20 meters.