Would an aromatic proton show up further downfield on a Proton Nuclear Magnetic Resonance (NMR) Spectrum than an aldehyde ?
The aldehyde would show up further downfield because its shift is around 10-12ppm while an aromatic proton shows up around 6-8ppm. The higher the number/more to the left on the spectrum the more downfield a proton is.
Which element is the most electronegative? A. Sodium B. Phosphorous C. Sulfur D. Fluorine
The correct answer is D. Fluorine because electronegativity increases as you go to the right of the periodic table and also increases as you go up the periodic table.
Solve for x: 4(x^2 - 1) = -x^2 + 16
4(x^2 - 1) = -x^2 + 16 4x^2 - 4 = -x^2 + 16 5x^2 = 20 x^2 = 4 x = 2 First, we use the distributive property and multiply 4 by both the x squared and the negative 1. Second, we add a positive x squared to the left side of the equation in order to get rid of it on the right side. And we also add positive 4 to the right side to eliminate it on the left. Third, we divide by 5 to get the x squared by itself. Lastly, we take the square root of both sides to get x by itself and the final value.