Tutor profile: Gabrielle G.
Subject: Study Skills
Tell me about a study strategy that you use and how it helps you maintain a healthy study schedule.
I set timers for the amount of time that I will be studying and the amount of time I will be on break. On days where I'm feeling particularly stressed, I only study for 25-30 minutes at a time and take a 5 minute break. On days when I'm feeling particularly energized, I study for 45 minutes at a time and take a 15 minute break. In both cases, I study for about 2-3 hours total. This varies between subject though, as I spend more time on subjects that I struggle with and less on subjects that I am strong in. Breaking up my study sessions into these more manageable chunks helps me feel less overwhelmed and retain the information I am reviewing better. This also helps me manage how much time I spend on each subject so that I don't spend too much time on one and not enough on another.
Explain the difference between active and passive transport in a cell and give an example of each.
Passive transport is the movement of particles down their concentration gradient (i.e. from high to low concentration), without the assistance of extra energy. Active transport is the process of moving particles against their concentration gradient (i.e. from low to high concentration) with the assistance of extra energy. This extra energy can come from coupling the movement of the particle with a different particle that is moving down its gradient. This coupling can occur in the same or opposite directions in the cell, known as symport or anitport, respectively. Active transport can also occur by using things like ATP hydrolysis, where the energy released from the hydrolysis of ATP provides the particles the energy they need to move against their gradient. An example of passive transport is osmosis, as water moves into/out of the cell according to the concentration gradient of the cell and its environmnet. An example of passive transport is the sodium potassium pump which uses ATP hydrolysis to move the two ions against their gradients. l
John owns a flower company. He wants to order bouquets of roses and sunflowers for an event. Roses cost $30 per bouquet, while sunflowers cost $20 per bouquet. If John spent $3,450 and has 150 bouquets total, how many bouquets of each flower did he buy?
First, we'll assign a variable to each flower. The number of rose bouquets John has will be "x" and the number of sunflower bouquets John has will be "y". John has 150 bouquets total, therefore, x + y = 150. We also know that 30x + 20y = 3,450, since John spent $3,450 total and roses cost $30 each and sunflowers cost $20 each. I decided to solve for the number of rose bouquets that John bought first. To do this, I first need to get y by itself in the equation x + y = 150. Therefore, y = 150 - x. Now that I know what y is equal to, I can plug it into my other equation so that it looks like this: 30x + 20(150-x) = 3,450. Since I only have one variable in the equation now (the variable x) I can solve for how many rose bouquets John bought. First, we distribute the 20 across the 150-x, which makes our equation look like this: 30x + 3000 - 20x. Next, I subtract 3,000 from the left and right side of the equal sign which leaves me with this: 30x -20x = 450. Then I combine my like terms (30x and 20x) leaving me with: 10x = 450. Finally, since I want to get x by itself, I divide 10x and 450 by 10, leaving me with x = 45. Now that I know what x is equal to, I can plug it into the equation x + y =150 and solve for the number of sunflowers John has: 45 + y = 150. Therefore, when I subtract 45 from the left and right sides of the equation, I'm left with y = 105. In the end, this means that John bought 45 bouquets of roses and 105 bouquets of sunflowers.
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