# Tutor profile: Ancy J.

## Questions

### Subject: Pre-Algebra

Solve y=3x+2 7x-4y=7. Find the value of x and y.

Given y= 3x+2. Here in 7x-4y= 7, we can replace y with 3x+2. It will become 7x-4(3x+2)= 7 open bracket by multiplying with 4 7x-(4*3x)+(-4*2)= 7 7x-12x-8= 7 here -4*3= -12 and -4*2= -8. -5x= 7+8 If we take -8 to another side of = it will become +8. x=15/-5= -3 To find y, substitute x in this equation. y= 3*-3 +2 Here put x= -3. = -9+2 = -7 So, x= -3 and y= -7. You solved it!!

### Subject: Basic Math

How to solve 6+2(8-4)=?

Here consider the bracket first. We can write it as 6+2(4) *here 8-4=4 Consider the left side of the operator "+" 6+8 *here 2*4=8 =14 Got it!!

### Subject: Number Theory

Solve 6+2(8-4)

First, solve the operations inside the bracket Here 8-4= 4 The expression will become 6+(2*4) That is 6+8 Here 2*4=8 =14 Got it!!

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