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Tutor profile: Tinsley B.

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Tinsley B.
Electrical Engineer Tutor_Member of Tau Beta Pi Engineering Honors Society
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Questions

Subject: Physics (Electricity and Magnetism)

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Question:

There is a node on a circuit with 2 currents coming in and 1 current exiting. a) If we know that one current into the node is $$i(1)=10 Amps$$ and the current leaving the node is $$i(3)=12$$ amps what is the other current entering the node $$i(2)=?$$. b) now that we found I(2), if the node has a voltage and I(2) runs across a 10 ohm resistor to ground what is the voltage at the node.

Inactive
Tinsley B.
Answer:

a) Here we apply Kirchoff's current law that all currents entering the node is equal to the currents exiting the node. $$10A+i(2)= 12A$$ $$i(2)=2A$$ b) Here we apply Ohm's Law $$\triangle(V)=I*R$$ $$(voltage @node-0)Volts=(2A)(10Ohms)$$ voltage at the node$$=20V$$

Subject: Electrical Engineering

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Question:

A resistor of 30 ohms is in series with a capacitor with an impedance of -j50 ohms and is also in series with an inductor with an impedance of j90 ohms. What is the total impedance, and which quadrant would the impedance vector lie in?

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Tinsley B.
Answer:

To find the total impedance, we add them together as follows: $$30+j90+(-j50)= 30 +j40$$ Therefore, our impedance vector would lie in quadrant 1.

Subject: Economics

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Question:

A manufacturing company will purchase a large piece of equipment for $5,000. Annual maintenance will be $100. The buyback at the end of 5 years is $1,000. What is the annual cost of the equipment at $$i=12$$%?

Inactive
Tinsley B.
Answer:

Step 1 find the A/P (annual based on the present) at 12% for the $5,000. We can use the table or the formula. For this problem, I will show the formula. $$\frac{(i(1+i)^n)} {((1+i)^n-1)}$$ we know $$i=12$$% which would be 0.12 and we know that $$n=5$$years. So, plugging those values into the formula we obtain 0.277409. We multiply this number by $5,000 to get the $$annual purchase cost=$1387.05$$ Step 2. find the A/F for the buyback. (annual based on future). Note that since the buyback is not a cost, it will be a subtracted value at the end. But the process is the same as in step 1. However, for this step, we will use the interest tables. rather than the A/F formula. First, go to the correct interest table. ours is 12%. Second, go to the correct column. Ours is the A/F column. Last go to the correct row for the year. Ours is 5 years. The value we found is 0.1574. Multiply this value by the buyback worth of $1,000 to find the $$annual buyback worth=$157.4 $$ Step 3 Combine all 3. Note the annual cost for maintenance is already in terms of annual cost so no modifications needed to be made. $$annual cost=annual purchase cost+annual maintenance-annual buyback worth$$ $$1387.05+100-157.40=1329.65$$ $$annual cost =$1329.65$$

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