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# Tutor profile: Darren O.

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Darren O.
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## Questions

### Subject:Pre-Algebra

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Question:

Simplify: (4*4)^2 + 4*4^2

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Darren O.

First, simplify within parentheses = (4*4) = 16^2 + 4*4^2 Second, simpligy exponents = 256 + 4*16 Third, multiply = 256 + 64 Finally, add = 320

### Subject:Basic Math

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Question:

A box weighs 54.4 lbs and contains 150 bolts. If the container itself weighs 2 lbs, how much does each bolt weigh?

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Darren O.

First, find the weight of the bolts by subtracting the weight of the container: 54.4 lbs - 2 lbs = 52.4 lbs Then, divide this amount by the total number of bolts to find the weight of each bolt: 52.4 lbs/150 = 0.349 lbs per bolt.

### Subject:Algebra

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Question:

The perimeter of a rectangular lost is 400 ft. The length of the lot is 10 ft more than twice the width. Find the dimensions of the lot.

Inactive
Darren O.

The formula for perimeter is 2L + 2W = P, where L represents the length, W represents the width, and P represents the perimeter. Recall that our perimeter is 400 ft. Therefore, our equation is 2L + 2W = 400. The length is 20 ft more than twice the width. "More than" equates to addition and "twice" represents multiplication by 2. L can be written as L = 2W + 20. Using substitution, our equation now looks like 2(2W+20) + 2W = 400. We now solve for W. First distribute: 2*2W+2*20 + 2W = 400 4W+40 + 2W = 400 Combine like terms: 4W+2W + 40 = 400 6W + 40 = 400 6W + 40 - 40 = 400 - 40 6W = 360 6W/6 = 360/6 W = 60 Now substitute 60 for W in L = 2W + 20. L = 2(60) + 20 L = 120 + 20 L = 140 The width of the rectangle is 60 ft and its length is 140 ft.

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